Remove Element | LeetCode 27

[Written explanation will be added soon]

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Here is the full implementation.

/**
 * @param {number[]} nums
 * @param {number} val
 * @return {number}
 */
let removeElement = function(nums, val) {
  let pointer1 = 0;

  for (let pointer2 = 0; pointer2 < nums.length; pointer2++) {
    if (nums[pointer2] !== val) {
      nums[pointer1] = nums[pointer2];
      pointer1++;
    }
  }

  return pointer1;
};